Integrand size = 27, antiderivative size = 134 \[ \int \frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{x^5} \, dx=-\frac {e^2 (13 d+8 e x) \sqrt {d^2-e^2 x^2}}{8 x^2}-\frac {d \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac {e \left (d^2-e^2 x^2\right )^{3/2}}{x^3}-e^4 \arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )+\frac {13}{8} e^4 \text {arctanh}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right ) \]
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Time = 0.15 (sec) , antiderivative size = 134, normalized size of antiderivative = 1.00, number of steps used = 9, number of rules used = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.296, Rules used = {1821, 825, 858, 223, 209, 272, 65, 214} \[ \int \frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{x^5} \, dx=e^4 \left (-\arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )\right )+\frac {13}{8} e^4 \text {arctanh}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right )-\frac {e^2 (13 d+8 e x) \sqrt {d^2-e^2 x^2}}{8 x^2}-\frac {d \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac {e \left (d^2-e^2 x^2\right )^{3/2}}{x^3} \]
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Rule 65
Rule 209
Rule 214
Rule 223
Rule 272
Rule 825
Rule 858
Rule 1821
Rubi steps \begin{align*} \text {integral}& = -\frac {d \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac {\int \frac {\sqrt {d^2-e^2 x^2} \left (-12 d^4 e-13 d^3 e^2 x-4 d^2 e^3 x^2\right )}{x^4} \, dx}{4 d^2} \\ & = -\frac {d \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac {e \left (d^2-e^2 x^2\right )^{3/2}}{x^3}+\frac {\int \frac {\left (39 d^5 e^2+12 d^4 e^3 x\right ) \sqrt {d^2-e^2 x^2}}{x^3} \, dx}{12 d^4} \\ & = -\frac {e^2 (13 d+8 e x) \sqrt {d^2-e^2 x^2}}{8 x^2}-\frac {d \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac {e \left (d^2-e^2 x^2\right )^{3/2}}{x^3}-\frac {\int \frac {78 d^7 e^4+48 d^6 e^5 x}{x \sqrt {d^2-e^2 x^2}} \, dx}{48 d^6} \\ & = -\frac {e^2 (13 d+8 e x) \sqrt {d^2-e^2 x^2}}{8 x^2}-\frac {d \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac {e \left (d^2-e^2 x^2\right )^{3/2}}{x^3}-\frac {1}{8} \left (13 d e^4\right ) \int \frac {1}{x \sqrt {d^2-e^2 x^2}} \, dx-e^5 \int \frac {1}{\sqrt {d^2-e^2 x^2}} \, dx \\ & = -\frac {e^2 (13 d+8 e x) \sqrt {d^2-e^2 x^2}}{8 x^2}-\frac {d \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac {e \left (d^2-e^2 x^2\right )^{3/2}}{x^3}-\frac {1}{16} \left (13 d e^4\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {d^2-e^2 x}} \, dx,x,x^2\right )-e^5 \text {Subst}\left (\int \frac {1}{1+e^2 x^2} \, dx,x,\frac {x}{\sqrt {d^2-e^2 x^2}}\right ) \\ & = -\frac {e^2 (13 d+8 e x) \sqrt {d^2-e^2 x^2}}{8 x^2}-\frac {d \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac {e \left (d^2-e^2 x^2\right )^{3/2}}{x^3}-e^4 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )+\frac {1}{8} \left (13 d e^2\right ) \text {Subst}\left (\int \frac {1}{\frac {d^2}{e^2}-\frac {x^2}{e^2}} \, dx,x,\sqrt {d^2-e^2 x^2}\right ) \\ & = -\frac {e^2 (13 d+8 e x) \sqrt {d^2-e^2 x^2}}{8 x^2}-\frac {d \left (d^2-e^2 x^2\right )^{3/2}}{4 x^4}-\frac {e \left (d^2-e^2 x^2\right )^{3/2}}{x^3}-e^4 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )+\frac {13}{8} e^4 \tanh ^{-1}\left (\frac {\sqrt {d^2-e^2 x^2}}{d}\right ) \\ \end{align*}
Time = 0.43 (sec) , antiderivative size = 127, normalized size of antiderivative = 0.95 \[ \int \frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{x^5} \, dx=-\frac {d \sqrt {d^2-e^2 x^2} \left (2 d^2+8 d e x+11 e^2 x^2\right )}{8 x^4}-\frac {13}{4} e^4 \text {arctanh}\left (\frac {\sqrt {-e^2} x-\sqrt {d^2-e^2 x^2}}{d}\right )+e \left (-e^2\right )^{3/2} \log \left (-\sqrt {-e^2} x+\sqrt {d^2-e^2 x^2}\right ) \]
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Time = 0.40 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.87
method | result | size |
risch | \(-\frac {\sqrt {-e^{2} x^{2}+d^{2}}\, \left (11 e^{2} x^{2}+8 d e x +2 d^{2}\right ) d}{8 x^{4}}-\frac {e^{5} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{\sqrt {e^{2}}}+\frac {13 e^{4} d \ln \left (\frac {2 d^{2}+2 \sqrt {d^{2}}\, \sqrt {-e^{2} x^{2}+d^{2}}}{x}\right )}{8 \sqrt {d^{2}}}\) | \(116\) |
default | \(d^{3} \left (-\frac {\left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{4 d^{2} x^{4}}+\frac {e^{2} \left (-\frac {\left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{2 d^{2} x^{2}}-\frac {e^{2} \left (\sqrt {-e^{2} x^{2}+d^{2}}-\frac {d^{2} \ln \left (\frac {2 d^{2}+2 \sqrt {d^{2}}\, \sqrt {-e^{2} x^{2}+d^{2}}}{x}\right )}{\sqrt {d^{2}}}\right )}{2 d^{2}}\right )}{4 d^{2}}\right )+e^{3} \left (-\frac {\left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{d^{2} x}-\frac {2 e^{2} \left (\frac {x \sqrt {-e^{2} x^{2}+d^{2}}}{2}+\frac {d^{2} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} x^{2}+d^{2}}}\right )}{2 \sqrt {e^{2}}}\right )}{d^{2}}\right )+3 d \,e^{2} \left (-\frac {\left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{2 d^{2} x^{2}}-\frac {e^{2} \left (\sqrt {-e^{2} x^{2}+d^{2}}-\frac {d^{2} \ln \left (\frac {2 d^{2}+2 \sqrt {d^{2}}\, \sqrt {-e^{2} x^{2}+d^{2}}}{x}\right )}{\sqrt {d^{2}}}\right )}{2 d^{2}}\right )-\frac {e \left (-e^{2} x^{2}+d^{2}\right )^{\frac {3}{2}}}{x^{3}}\) | \(324\) |
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Time = 0.28 (sec) , antiderivative size = 111, normalized size of antiderivative = 0.83 \[ \int \frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{x^5} \, dx=\frac {16 \, e^{4} x^{4} \arctan \left (-\frac {d - \sqrt {-e^{2} x^{2} + d^{2}}}{e x}\right ) - 13 \, e^{4} x^{4} \log \left (-\frac {d - \sqrt {-e^{2} x^{2} + d^{2}}}{x}\right ) - {\left (11 \, d e^{2} x^{2} + 8 \, d^{2} e x + 2 \, d^{3}\right )} \sqrt {-e^{2} x^{2} + d^{2}}}{8 \, x^{4}} \]
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Result contains complex when optimal does not.
Time = 4.42 (sec) , antiderivative size = 544, normalized size of antiderivative = 4.06 \[ \int \frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{x^5} \, dx=d^{3} \left (\begin {cases} - \frac {d^{2}}{4 e x^{5} \sqrt {\frac {d^{2}}{e^{2} x^{2}} - 1}} + \frac {3 e}{8 x^{3} \sqrt {\frac {d^{2}}{e^{2} x^{2}} - 1}} - \frac {e^{3}}{8 d^{2} x \sqrt {\frac {d^{2}}{e^{2} x^{2}} - 1}} + \frac {e^{4} \operatorname {acosh}{\left (\frac {d}{e x} \right )}}{8 d^{3}} & \text {for}\: \left |{\frac {d^{2}}{e^{2} x^{2}}}\right | > 1 \\\frac {i d^{2}}{4 e x^{5} \sqrt {- \frac {d^{2}}{e^{2} x^{2}} + 1}} - \frac {3 i e}{8 x^{3} \sqrt {- \frac {d^{2}}{e^{2} x^{2}} + 1}} + \frac {i e^{3}}{8 d^{2} x \sqrt {- \frac {d^{2}}{e^{2} x^{2}} + 1}} - \frac {i e^{4} \operatorname {asin}{\left (\frac {d}{e x} \right )}}{8 d^{3}} & \text {otherwise} \end {cases}\right ) + 3 d^{2} e \left (\begin {cases} - \frac {e \sqrt {\frac {d^{2}}{e^{2} x^{2}} - 1}}{3 x^{2}} + \frac {e^{3} \sqrt {\frac {d^{2}}{e^{2} x^{2}} - 1}}{3 d^{2}} & \text {for}\: \left |{\frac {d^{2}}{e^{2} x^{2}}}\right | > 1 \\- \frac {i e \sqrt {- \frac {d^{2}}{e^{2} x^{2}} + 1}}{3 x^{2}} + \frac {i e^{3} \sqrt {- \frac {d^{2}}{e^{2} x^{2}} + 1}}{3 d^{2}} & \text {otherwise} \end {cases}\right ) + 3 d e^{2} \left (\begin {cases} - \frac {e \sqrt {\frac {d^{2}}{e^{2} x^{2}} - 1}}{2 x} + \frac {e^{2} \operatorname {acosh}{\left (\frac {d}{e x} \right )}}{2 d} & \text {for}\: \left |{\frac {d^{2}}{e^{2} x^{2}}}\right | > 1 \\\frac {i d^{2}}{2 e x^{3} \sqrt {- \frac {d^{2}}{e^{2} x^{2}} + 1}} - \frac {i e}{2 x \sqrt {- \frac {d^{2}}{e^{2} x^{2}} + 1}} - \frac {i e^{2} \operatorname {asin}{\left (\frac {d}{e x} \right )}}{2 d} & \text {otherwise} \end {cases}\right ) + e^{3} \left (\begin {cases} \frac {i d}{x \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}}} + i e \operatorname {acosh}{\left (\frac {e x}{d} \right )} - \frac {i e^{2} x}{d \sqrt {-1 + \frac {e^{2} x^{2}}{d^{2}}}} & \text {for}\: \left |{\frac {e^{2} x^{2}}{d^{2}}}\right | > 1 \\- \frac {d}{x \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}}} - e \operatorname {asin}{\left (\frac {e x}{d} \right )} + \frac {e^{2} x}{d \sqrt {1 - \frac {e^{2} x^{2}}{d^{2}}}} & \text {otherwise} \end {cases}\right ) \]
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Time = 0.29 (sec) , antiderivative size = 171, normalized size of antiderivative = 1.28 \[ \int \frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{x^5} \, dx=-\frac {e^{5} \arcsin \left (\frac {e^{2} x}{d \sqrt {e^{2}}}\right )}{\sqrt {e^{2}}} + \frac {13}{8} \, e^{4} \log \left (\frac {2 \, d^{2}}{{\left | x \right |}} + \frac {2 \, \sqrt {-e^{2} x^{2} + d^{2}} d}{{\left | x \right |}}\right ) - \frac {13 \, \sqrt {-e^{2} x^{2} + d^{2}} e^{4}}{8 \, d} - \frac {\sqrt {-e^{2} x^{2} + d^{2}} e^{3}}{x} - \frac {13 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} e^{2}}{8 \, d x^{2}} - \frac {{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} e}{x^{3}} - \frac {{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} d}{4 \, x^{4}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 325 vs. \(2 (118) = 236\).
Time = 0.30 (sec) , antiderivative size = 325, normalized size of antiderivative = 2.43 \[ \int \frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{x^5} \, dx=\frac {{\left (e^{5} + \frac {8 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )} e^{3}}{x} + \frac {24 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{2} e}{x^{2}} + \frac {8 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{3}}{e x^{3}}\right )} e^{8} x^{4}}{64 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{4} {\left | e \right |}} - \frac {e^{5} \arcsin \left (\frac {e x}{d}\right ) \mathrm {sgn}\left (d\right ) \mathrm {sgn}\left (e\right )}{{\left | e \right |}} + \frac {13 \, e^{5} \log \left (\frac {{\left | -2 \, d e - 2 \, \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |} \right |}}{2 \, e^{2} {\left | x \right |}}\right )}{8 \, {\left | e \right |}} - \frac {\frac {8 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )} e^{5} {\left | e \right |}}{x} + \frac {24 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{2} e^{3} {\left | e \right |}}{x^{2}} + \frac {8 \, {\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{3} e {\left | e \right |}}{x^{3}} + \frac {{\left (d e + \sqrt {-e^{2} x^{2} + d^{2}} {\left | e \right |}\right )}^{4} {\left | e \right |}}{e x^{4}}}{64 \, e^{4}} \]
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Timed out. \[ \int \frac {(d+e x)^3 \sqrt {d^2-e^2 x^2}}{x^5} \, dx=\int \frac {\sqrt {d^2-e^2\,x^2}\,{\left (d+e\,x\right )}^3}{x^5} \,d x \]
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